Return a function pointer

Without a pre-defined function pointer type

float (*GetPtr1(const char opCode))(float, float) {    if(opCode == '+')       return &Plus;    else       return &Minus; // default if invalid operator was passed }

參考來源：

"float (*GetPtr1(const char opCode))(float, float)"
- The Function Pointer Tutorials - Syntax (在「Google 網頁註解」中檢視)